^aditi explain On Wed, Aug 31, 2011 at 12:08 PM, aditi garg <aditi.garg.6...@gmail.com>wrote:
> For ques 3,the ans shud be 2...but its not thr in the options... > > > On Wed, Aug 31, 2011 at 2:14 AM, icy` <vipe...@gmail.com> wrote: > >> For the third one by hand, I was just trying to keep track of 1-2 of >> the first digits for each section. >> >> I broke into sections as follows (^ to mean power here): >> >> 9! = (I just did this by hand, 1728x210=362880) , so we take 36. >> 10! to 19! = approx 1^10 = 1 >> 20! to 29! = approx 2^10 = 1024 = 10 >> 30! to 39! = approx 3^10 = 3, 6, 9, 27, 81, 243, 72.., 216.., 63..., >> 189.. = 1 >> 40! to 49! = 4^10 = 4, 16, 64, 25.., 10.., 4.. = this looked like a >> pattern, the tenth one should be 1.. again = 1 >> 50! to 59! = 5^10 = 5, 25, 125, 60.. , 30.., 150.., 75.., 37.., 18.., >> 90 = 9 >> 60! to 67! = 6^8 = 6, 36, 216, 126.. , 72..., 43.., 25.., 15.. = 1 >> >> so actually to correct what I had above, I was really looking to do >> 9*36 , (not 9*3=27), which gives about 324, or 3 for the first >> digit. This is just an approximation but it seems to work. >> >> On Aug 30, 4:06 pm, kartik sachan <kartik.sac...@gmail.com> wrote: >> > for 1st question ans will be a,b,e as (125)^1/3 is 5 sum is 8 >> > for 2nd question we see pattern in 7 power i.e 7,9,3,1 and this pattern >> > reapeats for inerval of 4 >> > and second term of of any power of 7>=2 is 4 >> > so diff is 5 >> > ans will be 5 >> > >> > how to find the ans of third question?? >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> >> > > > -- > Aditi Garg > Undergraduate Student > Electronics & Communication Divison > NETAJI SUBHAS INSTITUTE OF TECHNOLOGY > Sector 3, Dwarka > New Delhi > > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
