yes....we can print head 1 or head 2....will tell about the loop
On Aug 31, 6:18 pm, ravi maggon <maggonr...@gmail.com> wrote:
> In one of my interview at winshuttle I was asked the same ques but their was
> an addon to this. Find the point where the loop occurs.
> For eg:
> 1->2->3->4->5->6->7->8->9->5
>
> so output should be 5
>
> can anyone give the algo for this.
>
> On Wed, Aug 31, 2011 at 6:44 PM, Piyush Grover
> <piyush4u.iit...@gmail.com>wrote:
>
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>
> > This is fine but adding a twist to it.
> > Find number of nodes which are not in the loop.
>
> > On Wed, Aug 31, 2011 at 6:27 PM, rahul sharma
> > <rahul23111...@gmail.com>wrote:
>
> >> int loop(void *head1,void *head2)
> >> {
> >> //head1 and head2 initialized to start;
> >> while(head1!=NULL && head2!=NULL)
> >> {
> >> head1=head1->next;
> >> head2=head2->next->next;
> >> if(head1==head2)
> >> return 1;////tehre is loop;
> >> }
> >> return 0;//no loop
> >> }
>
> >> hi guys is it corect for finding the loop...if any test case that wont
> >> works here plz tell...
>
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> --
>
> Regards
> Ravi Maggon
> Final Year, B.E. CSE
> Thapar University
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