how abt this:
if(!a[0][0])
{
first traverse the 1st row till we find any 1...
On Sep 2, 12:32 pm, kranthi raj <kranthi...@gmail.com> wrote:
> oops missed Space Complexity
>
>
>
>
>
> On Fri, Sep 2, 2011 at 12:55 PM, kranthi raj <kranthi...@gmail.com> wrote:
> > for( i = 0 ; i < n ; ++i )
> > for( j = 0 ; j < m ; ++j )
> > if( a[i][j] != 0 )
> > row[j]=col[i]=1;
>
> > for( i = 0 ; i < n ; ++i )
> > for( j = 0 ; j < m ; ++j )
>
> > {
> > if (row[j]==1 || col[i]==1)
> > a[i][j]=1;
> > }
>
> > Does this work?
>
> --
> Sincerely,
> Kranthi Raj A
> 2nd Mtech
> Dept Of Computer Science ,
> Indian Institute of Technology, Madras
>
> #9884989577begin_of_the_skype_highlighting 9884989577 end_of_the_skype_highlighting
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