maintain a separate stack containing min and max element at each step.....
so if u pop an element for the original stack, pop from the second stack
also...


On Sun, Sep 4, 2011 at 11:13 PM, Deepak Garg <deepakgarg...@gmail.com>wrote:

> +1 sandeep
>
> On Sun, Sep 4, 2011 at 11:11 PM, SANDEEP CHUGH <sandeep.aa...@gmail.com>wrote:
>
>>
>> we can take another variable min..
>>
>> first time push operation is done , store the element into  min..
>>
>> next time push is performed , compare the number u r pushing with the
>> already stored no in "min"  variable.. and store minimum of two no's in min
>> variable.. and thn perform the push operation..
>>
>> so min always contain the minimum no...
>>
>> tell me will that approach work or not?
>>
>> On Sun, Sep 4, 2011 at 10:38 PM, Sangeeta <sangeeta15...@gmail.com>wrote:
>>
>>> How would you design a stack which,in addition to push and pop,also
>>> has a function min which returns the minimum element?push,pop and min
>>> should all operate in O(1) time
>>>
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>
>
>
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