@Mani: Easy calculus problem. Take the derivative of f(x) = sin^6(x) + cos^6(x), f'(x) = 5*sin^5(x)*cos(x) - 5*cos^5(x)*sin(x) and set it to zero. Solving gives x = n*pi/4, for n any integer. Furthermore, f is periodic with period pi/2. f(0) = 1, f(pi/4) = 1/4. So max = 1 and min = 1/4. The ratio max / min = 4.
Dave On Sep 4, 11:40 am, Mani Bharathi <manibharat...@gmail.com> wrote: > Find max and min ratio of sin^6x + cos^6x? -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
