well
#define SIZEOF(arr) (sizeof(arr)/sizeof(arr[0])) gives the number of
elements ie sizeof whole array /sizeof first element
second macro
#expr - prints variable name
and if value is preceded is 0 it means it s in octal formt.it is printed in
decimal format by conversion
hope i am clear
On Mon, Sep 5, 2011 at 7:48 PM, Mohit Goel <mohitgoel291...@gmail.com>wrote:
> 1) #include <stdio.h>
> #include <stdlib.h>
>
> #define SIZEOF(arr) (sizeof(arr)/sizeof(arr[0]))
>
> #define PrintInt(expr) printf("%s:%d\n",#expr,(expr))
> int main ()
> {
> /* The powers of 10 */
> int pot[] = {
> 0001,0010,0100,1000
>
> };
> int i;
>
> for(i=0;i<SIZEOF(pot);i++)
> PrintInt(pot[i]);
> return 0;
> }
>
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