This can be solve by considering following case:
i) If all the letters in the word are distinct : Just concatenate, reverse
of the string(excluding last letter) to the original word..e.g. ZXKH==>>ZXKH
KXZ
ii)If two letters are same in the word : First ignore all the letters
between those same words , and make left sub-string and right sub-string of
those *same letters* equal by adding letters.. e.g rzLkhmLty===>> rzyt
LkhmLtyzr And then apply rule i) for middle letters. e.g. rzytLkhmLtyzr
===>> rzytLkhmhkLtyzr
iii)If there are more than a *set of same letters* then first consider the
farthest set and make it palindrome using rule ii) , e.g.
ilOtPuyPuOer===>>ilreOtPuyPuOerli and move to next pair of same
letters i.e. P,P..(use recursion) and ignore last modified position of same
letters i.e.
O,O and again apply rule ii) e.g. ilreOtPuyPuOerli===>>>ilreOtuPuyPutOerli
And then finally use rule no i) for distinct
words..e.g.ilreOtuPuyPutOerli===>>ilreOtuPuyuPutOerli
On Sunday, 4 September 2011 19:54:35 UTC+5:30, learner wrote:
>
> Given a word, convert it into a palindrome with minimum addition of
> letters to it. letters can be added anywhere in the word. for eg if
> yahoo is given result shud be yahohay.
>
>
> Thanks
>
>
--
You received this message because you are subscribed to the Google Groups
"Algorithm Geeks" group.
To view this discussion on the web visit
https://groups.google.com/d/msg/algogeeks/-/Hsd6Tohi95oJ.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/algogeeks?hl=en.
