@Srivastav: Yeah. You need more parens:
printf("%d",(int)(3.14*6.25*6.25));
Without the extra parens, the 3.14 is cast to an int, but then
implicitly recast to a double for the multiplications. With the
parens, the product is formed in type double, and then the result is
cast into integer.
Sorry for not recognizing the need before.
Dave
On Sep 6, 5:18 pm, UTKARSH SRIVASTAV <usrivastav...@gmail.com> wrote:
> printf behaves abnormally when it sees arguments not matching with its
> datatype............
> @dave
> printf("%d",(int)3.14*6.25*6.25); is also giving 0.
>
> --
> *UTKARSH SRIVASTAV
> CSE-3
> B-Tech 3rd Year
> @MNNIT ALLAHABAD*
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