as per my knowledge
1)this is not swapping of the strings, use double indirection (use swap
function swap(char **t1, char **t2))
2)you cant change the address of the any array,(use change it to char
*t1="xyz",*t2="abc"; )
Thank you,
Sid.
On Wed, Sep 7, 2011 at 11:26 AM, piyush agarwal <pshagl...@gmail.com> wrote:
> #include<stdio.h>void swap(char *, char *);
> int main()
> {
> char *pstr[2] = {"Hello", "piyush"};
> swap(pstr[0], pstr[1]);
> printf("%s\n%s", pstr[0], pstr[1]);
> return 0;
> }void swap(char *t1, char *t2)
> {
> char *t;
> t=t1;
> t1=t2;
> t2=t;
> }
>
>
>
> --
> Piyush Agarwal
> Final Year Undergraduate
> Department of Computer Engineering
> Malaviya National Institute of Technology
> Jaipur
>
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