0xa == 0x 1010, which stands for all the even bits
0x5 == 0x 0101, which stands for all the odd bits
>>1 and <<1 means shifting odd to even and even to odd
then | means putting new even bits and odd bits together
Yanan Cao
On Wed, Sep 7, 2011 at 10:23 AM, teja bala <pawanjalsa.t...@gmail.com>wrote:
>
> Can anyone plzz xplain the code?
>
> public static int swapOddEvenBits(int x) {
> return ( ((x & 0xaaaaaaaa) >> 1) | ((x & 0x55555555) << 1) );
> }
>
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