Do reverse inorder and count number of nodes visited, Kth visited node will
be Kth largest.
Time : O(n)
Space : O(1)

On Mon, Sep 5, 2011 at 5:16 PM, bharatkumar bagana <
bagana.bharatku...@gmail.com> wrote:

> @monish:
> u'rs is correct , time =O(nlogn) Ok but, the constant behind this prog is
> very huge ..
> for every number coming in , u maintain minheap and maxheap,and also if the
> sizes are of mismatch , u delete from minheap and add that to max heap---
> here deletion--O(logn),addition--O(logn),this occurs on an average for
> every 3 elements ...
>
>
> On Mon, Sep 5, 2011 at 2:08 AM, sachin goyal <monugoya...@gmail.com>wrote:
>
>> @anup,@sukran ithink u both are right in case of binary search tree...
>> we can traverse and then easily find the value...
>> but in case of heap first we have to create the heap and accordingly apply
>> the algo the create min heap.....
>> it will be the complex program....
>> so simple is bst just traverse by inorder and compare
>> if anyone has simple solution or any other case then plz tell.....
>>
>>
>> On Sun, Sep 4, 2011 at 9:56 PM, monish001 <monish.gup...@gmail.com>wrote:
>>
>>> ALGO:
>>> 1. For each element 1 to k:
>>>       insert in into min-heap
>>> 2. for each element k+1 to n
>>>       delete the root of min-heap and insert this item into the min-
>>> heap
>>> 3. Finally you have a min-heap of k largest numbers and the root is
>>> your answer
>>>
>>> COMPLEXITY: O(n logn)
>>>
>>> -Monish
>>>
>>> On Sep 3, 3:03 pm, teja bala <pawanjalsa.t...@gmail.com> wrote:
>>> > //Asked in MS please help me with the coding or Give an algorithm
>>> >
>>> > Write code to return the kth largest element in a tree ...>>> function
>>> > prototype is int fucnkth(node *root,int k)
>>>
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>
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