no...it's close to zero but we can't compute it in terms of pi, R or so. We need to get number of points on the perimeter which is not possible with the standard method.
For the right-triangle. choose one random point and if second points is diametric to the first point then any third point on the circle will make it right triangle. or any two points amongst the three are diametric then it will form a right triangle. So...P = 3C2/nC3 now n-> infinite How to solve this?? On Sat, Sep 10, 2011 at 5:22 PM, Ishan Aggarwal < ishan.aggarwal.1...@gmail.com> wrote: > According to me, it should be 1/3 for each of the three options... > > > > On Sat, Sep 10, 2011 at 4:48 PM, Piyush Grover > <piyush4u.iit...@gmail.com>wrote: > >> Sorry guys.. I was wrong, radius also matters here... >> >> still investigating.... >> >> >> On Sat, Sep 10, 2011 at 3:56 PM, sarath prasath >> <prasathsar...@gmail.com>wrote: >> >>> @Piyush Grover: >>> please explain ur answer.... >>> >>> >>> On Sat, Sep 10, 2011 at 3:30 PM, Piyush Grover < >>> piyush4u.iit...@gmail.com> wrote: >>> >>>> I got.. >>>> >>>> 1.) 2/pi >>>> >>>> 2.) & 3.) 0.5 - (1/pi) >>>> >>>> >>>> On Sat, Sep 10, 2011 at 2:47 PM, Ishan Aggarwal < >>>> ishan.aggarwal.1...@gmail.com> wrote: >>>> >>>>> three points are randomly chosen on a circle.what the probability that >>>>> 1.triangle formed is right angled triangle. >>>>> 2.triangle formed is acute angled triangle. >>>>> 3.triangle formed is obtuse angled triangle. >>>>> >>>>> >>>>> -- >>>>> Kind Regards >>>>> Ishan Aggarwal >>>>> Phone : +91-9654602663 >>>>> >>>>> >>>>> -- >>>>> You received this message because you are subscribed to the Google >>>>> Groups "Algorithm Geeks" group. >>>>> To post to this group, send email to algogeeks@googlegroups.com. >>>>> To unsubscribe from this group, send email to >>>>> algogeeks+unsubscr...@googlegroups.com. >>>>> For more options, visit this group at >>>>> http://groups.google.com/group/algogeeks?hl=en. >>>>> >>>> >>>> -- >>>> You received this message because you are subscribed to the Google >>>> Groups "Algorithm Geeks" group. >>>> To post to this group, send email to algogeeks@googlegroups.com. >>>> To unsubscribe from this group, send email to >>>> algogeeks+unsubscr...@googlegroups.com. >>>> For more options, visit this group at >>>> http://groups.google.com/group/algogeeks?hl=en. >>>> >>> >>> -- >>> You received this message because you are subscribed to the Google Groups >>> "Algorithm Geeks" group. >>> To post to this group, send email to algogeeks@googlegroups.com. >>> To unsubscribe from this group, send email to >>> algogeeks+unsubscr...@googlegroups.com. >>> For more options, visit this group at >>> http://groups.google.com/group/algogeeks?hl=en. >>> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > > > -- > Kind Regards > Ishan Aggarwal > [image: Aricent Group] > Presidency Tower-A, M.G.Road,Sector-14 > Gurgaon,Haryana.122015 INDIA > Phone : +91-9654602663 > ishan2.aggar...@aricent.com <puneet.ar...@aricent.com> > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
