yes for integer arrays we need to sort o(nlogn) and den compare in o(n)

On Sat, Sep 10, 2011 at 7:12 PM, Ishan Aggarwal <
ishan.aggarwal.1...@gmail.com> wrote:

> Hi,
>
> Actually I am not good at hash tables. can u plzz suggest me some gud link
> from where I can study hash tables...
> and also tell me the logic for integer arrays for which the complexity will
> be o(n logn).
>
> Thanks in advance.
>
>
> --
> Kind Regards
> Ishan Aggarwal
> Phone : +91-9654602663
>
>
> On Sat, Sep 10, 2011 at 7:03 PM, Brijesh <brijeshupadhyay...@gmail.com>wrote:
>
>> If you are talking about character array then it can be done in space
>> O(128)=constant and time O(n),,. as Use Hash table of all 128 characters ,
>> and then traverse through your array and mark a flag in the hash table..when
>> you encounter any duplicate character , which would be marked already in the
>> hash table , dont print it..!
>>
>> And if its integer array... best would be sort it in O(n logn) and
>> traverse through the loop and print those  numbers which are not same as
>> previous number..
>>
>> On Saturday, 10 September 2011 14:51:18 UTC+5:30, Ishan Aggarwal wrote:
>>
>>> Write a program to remove duplicate elements from an array by printing
>>> them only once?
>>>
>>> What will be the minimum time and space complexity required for this
>>> program?
>>>
>>> --
>>> Kind Regards
>>> Ishan Aggarwal
>>> [image: Aricent Group]
>>> Presidency Tower-A, M.G.Road,Sector-14
>>> Gurgaon,Haryana.122015 INDIA
>>> Phone : +91-9654602663
>>> ishan2....@aricent.com
>>>
>>>   --
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