no. are from 1 to 99 , by sum of n numbers formula we ve sum(99)= (99*998)/2
but here we have an array a[100] with a repeated element.Sum of the numbers in this array is for(i=1;i<100;i++) { sum1+=a[i]; } repeated element = sum(99)-sum1; -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.