2  question

numbers are (a1+1)*a2*a3... an = a1*a2*a3...an + a2*a3...an
the first term is same...
for second term is (a1*a2...an)/(a1)
now we have to find max of ( ((a1*a2..an)/a1),  (a1*a2...an)/a2....)
so the question of max becomes min of( a1, a2, a3... an)


-- 
Ankit Agarwal
Computer Science & Engg.
Integrated Dual Degree, V yr
Department of Electronics & Computer Engineering
Indian Institute of Technology Roorkee
Ph. no. +91-9580098805

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