take an array containing all original upper-case letters and their smaller
case letters and now the problem is reduced to print all substrings
containing length of original string.
On Wed, Sep 14, 2011 at 8:55 PM, teja bala <pawanjalsa.t...@gmail.com>wrote:
>
> //dis one works check it out..............
>
> #include<ctype.h>
> #include<stdio.h>
> #include<string.h>
> #include<assert.h>
> void toggler(char* x, int pos)
> {
> if(pos==0){ printf("%s\n",x); return; }
> // printf("String is now: %s\n",x);
> x[pos-1] = toupper(x[pos-1]);
> toggler(x, pos-1);
> x[pos-1] = tolower(x[pos-1]);
> toggler(x, pos-1);
> return;
> }
> int main(void){
> char str[500];
> scanf("%s",str);
> toggler(str, strlen(str));
> return 0;
> }
>
> On Wed, Sep 14, 2011 at 7:22 PM, Dave <dave_and_da...@juno.com> wrote:
>
>> @Teja: Oops. I was wrong. By the time I fix my conceptual error, the
>> code is no shorter than Anshu's.
>>
>> Dave
>>
>> On Sep 14, 8:14 am, teja bala <pawanjalsa.t...@gmail.com> wrote:
>> > @DAVE
>> >
>> > dis was the o/p for ur prog.
>> >
>> > aBC
>> > abC
>> > abC
>> > abc
>> > abc
>> > abc
>> > abc
>> > abc
>> >
>> > #include<iostream.h>
>> > main()
>> > {
>> > int i, n = 3;
>> > char *s="ABC";
>> > for( i = 0 ; i < (1<<n) ; ++i )
>> > {
>> > s[i^(i>>1)] ^= 'a' ^ 'A';
>> > cout << s << endl;
>> >
>> >
>> >
>> > }
>> > }- Hide quoted text -
>> >
>> > - Show quoted text -
>>
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