solution is =3 with the condition p!=0 and q!=0 and r!=0
Ashima
M.Sc.(Tech)Information Systems
4th year
BITS Pilani
Rajasthan




On Thu, Sep 15, 2011 at 10:38 PM, Piyush Grover
<piyush4u.iit...@gmail.com>wrote:

> @abhinav...
>
> it's not about being over smart or to show someone or to prove someone
> anything. It's just that
> you should not take any assumptions by yourself or if you do you should
> specify clearly.
> If u r asked this question in an interview and you give the answer 3
> without telling your assumption, u r done!!
>
> And if you are living in the programming world, you need to take care of
> all the possible scenarios otherwise u will end up throwing exceptions and
> segmentation faults.
>
>
>
> On Thu, Sep 15, 2011 at 10:32 PM, Don <dondod...@gmail.com> wrote:
>
>> Right, and in every proof above, at some point there is a possible
>> division by zero. Therefore the proof is not valid in cases where R or
>> P or Q are zero, and there are infinitely many such cases.
>> The problem states P+Q+R=0 as the only constraint. There are
>> infinitely many cases which fit that constraint where the expression
>> is not equal to 3.
>> Don
>>
>> On Sep 15, 11:57 am, abhinav gupta <guptaabhinav...@gmail.com> wrote:
>> > u cnt divide a number by 0..that thing is self undrstod,,,,
>> >
>> > On Thu, Sep 15, 2011 at 9:49 AM, Piyush Grover <
>> piyush4u.iit...@gmail.com>wrote:
>> >
>> >
>> >
>> > > Don is right....
>> >
>> > > if R = 0, P = 1 and Q = -1 then the given expression is UNDEFINED!!!
>> >
>> > > On Thu, Sep 15, 2011 at 10:16 PM, abhinav gupta <
>> guptaabhinav...@gmail.com
>> > > > wrote:
>> >
>> > >> Shut up...its 3,,
>> >
>> > >> On Thu, Sep 15, 2011 at 9:43 AM, Don <dondod...@gmail.com> wrote:
>> >
>> > >>> It might be 3, but it doesn't have to be 3.
>> > >>> Don
>> >
>> > >>> On Sep 14, 11:56 pm, NAGARAJAN SIVARAMAN <naga4...@gmail.com>
>> wrote:
>> > >>> > if P+Q+R= 0  then P2 /QR  + Q2/PR + R2/PQ = ??
>> >
>> > >>> > how to solve this??
>> >
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>> > >> --
>> > >> @ |3  # ! /\/ @ \./
>> >
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