1: use bit array(hashing) then only it is possible in O(n)

On Fri, Sep 16, 2011 at 12:04 PM, tech coder <techcoderonw...@gmail.com>wrote:

> @ akshat   read the question properly  before posting such  solution
>
>
> On Wed, Aug 31, 2011 at 12:27 PM, Akshat Sapra <sapraaks...@gmail.com>wrote:
>
>> Solution:
>>
>> arr[n],sum = 0;
>>
>>
>> for ( int i = 0 ; i < n; i++ ) {
>>        sum ^= arr[i];
>> }
>>
>> print sum; // required number
>>
>> --
>>
>>
>> Akshat Sapra
>> Under Graduation(B.Tech)
>> IIIT-Allahabad(Amethi Campus)
>> --------------------------------------
>> sapraaks...@gmail.com
>> akshatsapr...@gmail.com
>> rit2009...@iiita.ac.in
>> sapraaks...@facebook.com
>>
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>
>
>
> --
> *
>
>  Regards*
> *"The Coder"*
>
> *"Life is a Game. The more u play, the more u win, the more u win , the
> more successfully u play"*
>
>


-- 
*

 Regards*
*"The Coder"*

*"Life is a Game. The more u play, the more u win, the more u win , the more
successfully u play"*

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