x==9 is not an error...
it will be 1 when true and 0 when false...and both are executable
statements...
when we print float with %d then compiler prints 0...and when we print
integer with %f then compiler prints last assigned or printed float value to
any float variable....here it is assigned for t.. so it will print t again
and again
...
On Sat, Sep 17, 2011 at 11:39 AM, praveen raj <praveen0...@gmail.com> wrote:
> This will show syntax error due to x==9 and otherwise since memory address
> given at the declarAtion there fore x value will. Change at every
> assignment , but i m not sure printf will give an error or not . Plz reply.
>
> On 17-Sep-2011 1:13 AM, "Anshul AGARWAL" <anshul.agarwa...@gmail.com>
> wrote:
> >
> > #include<stdio.h>
> > int main()
> > {float t;
> > long x;
> >
> >
> > t=98;
> > printf("%d\n",t);
> > printf("%f\n",x);
> > {
> > x=1;
> > printf("%f\n",x);
> > {
> >
> > x=30;
> > printf("%f\n",x);
> > }
> > printf("%f\n",x);
> > }
> > x==9;
> > printf("%f\n",x);
> >
> > }
> > ----------------
> > -----------------------------------------------------------
> > Anshul Agarwal
> > Nit Allahabad
> > Computer Science
> >
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