@balaji +1 :)
On Thu, Sep 22, 2011 at 2:01 PM, Anil Arya <anilarya...@gmail.com> wrote:
> thanx Balaji....:)
>
>
> On Thu, Sep 22, 2011 at 6:07 AM, Balaji <balaji.subraman...@gmail.com>wrote:
>
>> Hi Anil,
>>
>> #a is a preprocessor operator to convert the argument specified as string
>> or enclosing in double quotes. so, after macro expansion, the printf
>> statement would become
>>
>> printf("%d\n",*"432"); =>
>>
>> printf("%d\n","432"[0]);=>
>>
>> printf("%d\n",*"4");
>>
>> which prints the ASCII equivalent 52.
>>
>>
>> Similarly, using printf("%d\n", "432"[1]),printf("%d\n", "432"[2]) would
>> yield 52 and 51 respectively. Let me know.
>>
>>
>> Thanks,
>>
>> Balaji
>>
>>
>>
>> On Wed, Sep 21, 2011 at 4:34 PM, Anil Arya <anilarya...@gmail.com> wrote:
>>
>>>
>>>
>>>
>>>
>>> #include<stdio.h>
>>>
>>> #define power(a) #a
>>>
>>> int main(){printf("%d\n",*power(432));return 0;}
>>>
>>> why it is giving 52 as output?
>>>
>>>
>>>
>>>
>>>
>>> --
>>> *Anil Arya,
>>> Computer Science *
>>> *Motilal Nehru National Institute of Technology,Allahabad .
>>> *
>>>
>>>
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>
>
>
> --
> *Anil Arya,
> Computer Science *
> *Motilal Nehru National Institute of Technology,Allahabad .
> *
>
>
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--
AMRIT
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