m sry i dint read the question properly
page no = vitual page % 3 ie 0 % 3 = 3
thrfre 3*1024 is starting addr of physical page
but the byte address will be 3*1024 + 512 = 3584

On Sun, Sep 25, 2011 at 10:12 AM, Vishnu Ganth <crazyvishnu...@gmail.com>wrote:

> 3584
>
>
> On Sun, Sep 25, 2011 at 9:53 AM, sivaviknesh s <sivavikne...@gmail.com>wrote:
>
>>
>>
>>
>> Consider a virtual memory system in which the virtual page addresses are
>> mapped onto physical page addresses as follow
>> Virtual page address...................... Physical page address
>> 0........................................................................3
>> 1........................................................................2
>> 2.......................................................................1
>> The address of any byte in this system is given by the ordered pair (v,d)
>> where v = virtual page address d = byte offset in the page
>> Assuming that the main memory is capable of holding 4 page frames, what is
>> the physical address of a byte having the virtual address (0,512) given that
>> the page size is 1024 bytes?
>> a) 3584
>> b) 2560
>> c) 1536
>> d) 512
>> e) 1024
>>
>>
>> --
>> Regards,
>> $iva
>>
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>
>
>
> --
> ~VISHNU~
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