ok.. thanks guys...
one doubt now... if this ques is asked in an interview(its already been
asked in ms interview)... then u cant just write the code... u hv to explain
the whole approach like why u r choosing that way to narrowing dowm the
range...

so pls explain how this sol is derived...

On Sun, Sep 25, 2011 at 10:15 AM, keyan karthi <keyankarthi1...@gmail.com>wrote:

> binary search!!! :)
>
>
> On Sat, Sep 24, 2011 at 11:38 PM, sunny agrawal 
> <sunny816.i...@gmail.com>wrote:
>
>> let x be the number
>> initialize ans to some value like x or x/2
>>
>> now repeatedly do the following
>> ans  = (ans + x/ans)/2
>> each time you perform this operation you will move closer to the sqrt
>> value and depending upon the precision required stop
>>
>>
>>
>>
>> On Sat, Sep 24, 2011 at 11:17 PM, siddharth srivastava <
>> akssps...@gmail.com> wrote:
>>
>>>
>>>
>>> On 24 September 2011 13:45, shady <sinv...@gmail.com> wrote:
>>>
>>>> one of the simplest way is to do binary search... :)
>>>
>>>
>>> +1
>>>
>>>
>>>>
>>>>
>>>> On Sat, Sep 24, 2011 at 8:42 PM, teja bala 
>>>> <pawanjalsa.t...@gmail.com>wrote:
>>>>
>>>>> http://www.geeksforgeeks.org/archives/3187
>>>>>
>>>>>
>>>>> check dis one.............
>>>>>
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>>>
>>>
>>>
>>> --
>>> Regards
>>> Siddharth Srivastava
>>>
>>>
>>>
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>>
>>
>>
>> --
>> Sunny Aggrawal
>> B.Tech. V year,CSI
>> Indian Institute Of Technology,Roorkee
>>
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