Q1
int fun(int arr[],int left,int right,int num)
{
int mid=(left+right)/2;
if(mid==0)
return 0;
if(mid==num-1)
return 1;
if( arr[mid]<arr[mid-1] && arr[mid]<=(arr[mid]+1))
return (num-mid);
else if(arr[mid]>=arr[left])
return fun(arr,mid+1,right,num);
else if(arr[mid]<=arr[left])
return fun(arr,left,mid-1,num);
}
fun(arr,0,size-1,size)
COrrect Me if am wrong..
On Sun, Sep 25, 2011 at 9:39 PM, prasanth n <nprasnt...@gmail.com> wrote:
> @ Decipher:
> Q1) find where the rotation begins and do binary search in the first half
> or the second half depending upon the search element
>
>
> On Sun, Sep 25, 2011 at 8:58 PM, Decipher <ankurseth...@gmail.com> wrote:
>
>> Q1) A sorted array is rotated unknown number of times , write an algorithm
>> to search an element in this rotated array in O(log n) .
>> Hint : Modify binary search
>>
>> Q2) Write an algorithm to traverse a rectangular matrix spirally.
>>
>>
>>
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>
>
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> *prasanth*
>
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--
*Dheeraj Sharma*
Comp Engg.
NIT Kurukshetra
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