http://www.ideone.com/tY7jM
On Wed, Sep 28, 2011 at 8:13 PM, sreeprasad.sp <sreeprasad...@gmail.com>wrote: > > > public class firstNonRepeatedCharInString { > > public static void main(String abc[]){ > > firstNonRepeatedCharInString f = new firstNonRepeatedCharInString(); > String checkString="bbzbccdede"; > String checkString1="bzzzzzzccde"; > String checkString2="abcdef"; > String checkString3="aabc"; > String checkString4="zzzzzzcc"; > int index=f.getIndexOfFirstNonRepeatingChar(checkString); > if(index!=-1) > System.out.println("the first non repeating character in " +checkString > +" is at "+checkString.charAt(index)); > else > System.out.println("there is no repeating character in " +checkString > ); > > index=f.getIndexOfFirstNonRepeatingChar(checkString1); > if(index!=-1){ > System.out.println("the first non repeating character in " > +checkString1 +" is at "+checkString1.charAt(index)); > }else > System.out.println("there is no repeating character in " > +checkString1 ); > > > index=f.getIndexOfFirstNonRepeatingChar(checkString2); > if(index!=-1) > System.out.println("the first non repeating character in " > +checkString2 +" is at "+checkString2.charAt(index)); > else > System.out.println("there is no repeating character in " +checkString2 > ); > > index=f.getIndexOfFirstNonRepeatingChar(checkString3); > if(index!=-1) > System.out.println("the first non repeating character in " > +checkString3 +" is at "+checkString3.charAt(index)); > else > System.out.println("there is no repeating character in " +checkString3 ); > > index=f.getIndexOfFirstNonRepeatingChar(checkString4); > if(index!=-1) > System.out.println("the first non repeating character in " > +checkString4 +" is at "+checkString4.charAt(index)); > else > System.out.println("there is no repeating character in " +checkString4 > ); > } > > public int getIndexOfFirstNonRepeatingChar(String checkString){ > char [] toCharArray = checkString.toCharArray(); > if(toCharArray.length==1) > return 0; > else if(toCharArray.length==2) { > if(toCharArray[0]==toCharArray[1]) return -1; > }else if(toCharArray.length==3){ > if (((checkString.charAt(0))!=(checkString.charAt(1))) && > (checkString.charAt(1) != checkString.charAt(2))){ > return 0; > }else if((checkString.charAt(0)==checkString.charAt(1)) && > (checkString.charAt(1)!=checkString.charAt(2))){ > return 2; > }else if( (checkString.charAt(0)!=checkString.charAt(1)) && > (checkString.charAt(1)==checkString.charAt(2))) > return 0; > } > > > else{ > for(int i=0;i<toCharArray.length-2;i++){ > if (((checkString.charAt(i))!=(checkString.charAt(i+1))) && > (checkString.charAt(i+1) != checkString.charAt(i+2))){ > return i; > }else if( (checkString.charAt(i) != checkString.charAt(i+1)) && > (checkString.charAt(i+1)==checkString.charAt(i+2))){ > if(i-1<0){ > return i; > }else{ > > > if( (checkString.charAt(i-1)==(checkString.charAt(i))) && > (checkString.charAt(i+1)==checkString.charAt(i+2))) > continue; > else > return i;} > > }else if( (checkString.charAt(i)== checkString.charAt(i+1)) && > (checkString.charAt(i+1)!=checkString.charAt(i+2))){ > if( (i+3)<=checkString.length() ){ > if(checkString.charAt(i+2)!=checkString.charAt(i+3)){ > return i+2; > }else{ > continue; > } > > }else {return i+2;}} > } > } > > return -1; > > } > } > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To view this discussion on the web visit > https://groups.google.com/d/msg/algogeeks/-/AgtYjYsCg1UJ. > > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- Saurabh Singh B.Tech (Computer Science) MNNIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.