Sorry!

you want to find the following sum:
F (0) + F (3) + F (6) + ... + F (3n) =?

I do not know any formula for this sum.

This formula may help here:

F (0) + F (1) + F (2) + F (3 )+...+ F (n) = F (n +2) - 1

F (3n) = 3F (n) ^ 3 + 3 (-1) ^ nF (n)

You can prove this by induction!


Wladimir Araujo Tavares
*Federal University of CearĂ¡ <http://lia.ufc.br/%7Ewladimir/>
Homepage <http://lia.ufc.br/%7Ewladimir/> |
Maratona<https://sites.google.com/site/quixadamaratona/>|
*




On Sat, Oct 1, 2011 at 2:29 PM, rahul sharma <rahul23111...@gmail.com>wrote:

> yeah like0 1 1 3 5 8 .........only even shpuld be added 0+8......u r ryt
>
>
> On Sat, Oct 1, 2011 at 10:56 PM, Shuaib Khan <aries.shu...@gmail.com>wrote:
>
>> I am I not wrong, the problem asks for fib numbers which are even, not fib
>> numbers with even index...?
>>
>>
>> On Sat, Oct 1, 2011 at 10:16 PM, Wladimir Tavares 
>> <wladimir...@gmail.com>wrote:
>>
>>> F(0)+F(2)+...+F(2n) = F(2n+1) - 1
>>>
>>>
>>> Wladimir Araujo Tavares
>>> *Federal University of CearĂ¡ <http://lia.ufc.br/%7Ewladimir/>
>>> Homepage <http://lia.ufc.br/%7Ewladimir/> | 
>>> Maratona<https://sites.google.com/site/quixadamaratona/>|
>>> *
>>>
>>>
>>>
>>>
>>>
>>> On Sat, Oct 1, 2011 at 1:40 PM, rahul sharma <rahul23111...@gmail.com>wrote:
>>>
>>>> nyone provide me with recursive sol of the following prob.....
>>>>
>>>>
>>>> find the sum of all even nos. in the fibbonacci series upto 1000....thnx
>>>> in davance
>>>>
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>>
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>> Shuaib
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