Code for Compression
I am doing it inplace
void convert(char* s,int len){
int i=0;
int count=1;
int index=1; //*maintain the index where number is to be added*
for(i=1;i<=len;i++){
if(s[i]==s[i-1])
count++;
else{
s[index-1]=s[i-1];*//put the char first like a3abbb . then this
step converts it into a3bbbb*
s[index]= (count+'0');/*/convert the count integer into char so
it becomes a3b4bb*
count=1;
index = index+2;
}
}
s[index-1]='\0'*;//terminate the string* *(a3b4bb will become a3b4)*
}
On Mon, Oct 3, 2011 at 12:12 PM, rahul sharma <rahul23111...@gmail.com>wrote:
> check my code for compression..
>
> check if it is ok
> abc i/p
> o/p abc
>
> means if character has no count.but still present in string it is its only
> occurance.....plz check that code...
>
> #include<iostream.h>
> #include<conio.h>
> int main()
> {
> cout<<"\nenter the string";
> char str[30];
> cin>>str;
> int c=1;
> for(int i=0;str[i];i++)
> {
> if(str[i+1]>='0' && str[i+1]<='9')
> {
> c=c+(str[i+1]-'0');
> for(int j=1;j<c;j++)
> cout<<str[i];
> i++;
>
> }
>
> else
> cout<<str[i];
> c=1;
>
>
> }
>
> getch();
>
> }
>
>
>
> On Mon, Oct 3, 2011 at 12:08 PM, Rahul Verma <rahulverma....@gmail.com>wrote:
>
>> @rahul sharma
>>
>> for that you have to check that string is alphanumeric or not. if it is
>> alphanumeric then you have to call the function exapansion else you have to
>> call the compression function.
>>
>> and
>>
>> if the desired output for *abc *is *a1b1c1* then you have to call the
>> *exapnsion
>> function* or if the desired output is *abc* then you have to add a
>> feature in the *compression function* i.e. in output the string have to
>> omit the 1's
>>
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