@amol
I was not sure that for every number that has 3 in its unit place has one
multiple which has all one. So I used that is if the remainder is coming
that already appeared stop there coz it will make stuck in a loop.
for ex. remainders are
1 3 19 23 37 1 3 19 .... that will repeat.
but it in this case u can remove the set. Code will look more simpler.
string all1Multiple(int x)
{
string s;
int r=1;
do
{
s += '1';
r = r % x;
r = r * 10 + 1;
} while(r != 1);
return s;
}
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