Any natural no can be written as a product of powers of primes

N  = a^m × b^n × c^l where a, b , c are prime no.s
for given N= 8 × 33
N= 2^3 × 3^1 × 11^1
now we can use combinatorics to find 2 distinct factors a × b such that
(a,m)=1 i.e. they are co-primes

On 28 October 2011 20:21, SAMMM <somnath.nit...@gmail.com> wrote:

> If a natural number N is given such that N = a × b where a and b are
> the factors of N. How many such sets of (a, b) can be formed in which
> the selection of the two numbers a and b is distinctly different if N
> = 8 × 33 and the distinct factors should be Prime to each other ?
>
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