wen u write something in printf, its 1st stored in the stdout buffer, and
then wen buffers gets filled up, it goes to std output, u can forcly flush
it by using a fflush(stdout) api aftr ur printf st, or by putting a new
ln..
On Fri, Nov 11, 2011 at 12:49 PM, rachel <asret...@gmail.com> wrote:
> oh, so what you want to say is that when '\n' is not there in print
> command and then it is stored in stdout buffer unless it receives a '\n'
> and executes only in the end if '\n' is not received.
>
> thanks rahul :)
>
>
> On Fri, Nov 11, 2011 at 12:31 PM, rahul vatsa <vatsa.ra...@gmail.com>wrote:
>
>> u have a new line in 2nd prog bt not in the st, that makes the difference.
>> when u do fork in 1st code, the "algo" is nt printed on the terminal,
>> rather it is in the stdout buffer oly, which gets duplicated in the forked
>> pr also. nd wen the prog terminates, whtver is ther in the buffer gets
>> printed on terminal.
>> bt in the 2nd code, due to new line, it gets flushed off before fork, nd
>> so the forkd pr doesn't print this.
>>
>> On Fri, Nov 11, 2011 at 12:22 PM, rachel <asret...@gmail.com> wrote:
>>
>>> main()
>>> {
>>> printf("algo ");
>>> fork();
>>> // do anything
>>> }
>>> in this program, it is printing "algo" two times.
>>>
>>>
>>> main()
>>> {
>>> printf("algo \n");
>>> fork();
>>> // do anything
>>> }
>>> in this program, it is printing "algo" only once.
>>>
>>> when a fork() is done, processes gets doubled and the execution starts
>>> from the part of the program below the fork() command, am i correct ?
>>>
>>> Thanks in advance.
>>>
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