yup rite...it should be O(k log n ) not O(n log n). On Wed, Dec 14, 2011 at 11:44 AM, Dave <dave_and_da...@juno.com> wrote:
> @Atul: The initial heap is given. You have to maintain the heap > property as k elements are removed, which is O(k log n). This does not > satisfy the original request for an algorithm that is "O(k) in the > worst-case, independent of the size of the heap." > > Dave > > On Dec 13, 10:31 pm, atul anand <atul.87fri...@gmail.com> wrote: > > @gaurav : you need to first build heap and then maintain heap property > ever > > time you remove element.so this would take O(n logn ). > > > > > > > > On Wed, Dec 14, 2011 at 1:38 AM, Gaurav Kumar <gkuma...@gmail.com> > wrote: > > > Why can't we keep removing the minimum element each time and compare it > > > with x? This should take O(k) time since in a Min heap, the minimum > element > > > can be removed in O(1) time? Am I missing something? > > > > > On Tue, Dec 13, 2011 at 8:43 AM, atul anand <atul.87fri...@gmail.com > >wrote: > > > > >> O(k) in the worst-case , then i guess it would better to use > > >> median-of median algo to find element at rank k. and comparing with x. > > > > >> or > > >> we can us hashtable to solve this. > > > > >> On Tue, Dec 13, 2011 at 3:23 PM, Ankur Garg <ankurga...@gmail.com> > wrote: > > > > >>> Given an array-based heap on n elements and a real number x, > efficiently > > >>> determine whether the kth smallest element in the heap is greater > than or > > >>> equal to x. Your algorithm should be O(k) in the worst-case, > independent of > > >>> the size of the heap. > > > > >>> This question was also asked in Amazon > > > > >>> -- > > >>> You received this message because you are subscribed to the Google > > >>> Groups "Algorithm Geeks" group. > > >>> To post to this group, send email to algogeeks@googlegroups.com. > > >>> To unsubscribe from this group, send email to > > >>> algogeeks+unsubscr...@googlegroups.com. > > >>> For more options, visit this group at > > >>>http://groups.google.com/group/algogeeks?hl=en. > > > > >> -- > > >> You received this message because you are subscribed to the Google > Groups > > >> "Algorithm Geeks" group. > > >> To post to this group, send email to algogeeks@googlegroups.com. > > >> To unsubscribe from this group, send email to > > >> algogeeks+unsubscr...@googlegroups.com. > > >> For more options, visit this group at > > >>http://groups.google.com/group/algogeeks?hl=en. > > > > > -- > > > You received this message because you are subscribed to the Google > Groups > > > "Algorithm Geeks" group. > > > To post to this group, send email to algogeeks@googlegroups.com. > > > To unsubscribe from this group, send email to > > > algogeeks+unsubscr...@googlegroups.com. > > > For more options, visit this group at > > >http://groups.google.com/group/algogeeks?hl=en. > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.