@Sourabh

m=2^s***d
primes[i]*<*n



On 2012-1-18 19:39, Sourabh Singh wrote:
@Terrence

sry i didn't explain what s,d were they were also wrong i ws
calculating for n not n-1
earlier  n=2^s+d

nw m=n-1;      for odd n
      m=2^s+d;

//suggested corrections made.. still not working..
#include<iostream>
#include<conio.h>
#include<math.h>
using namespace std;
int is_prime(int n)
{
         if(n==2 | n==3)
                       return 1;
         if(((n-1)%6!=0&  (n+1)%6!=0) || n<2)
                       return 0;
         int m=n-1;
         int s,d;
         for(s=0;1<<s<m;++s); s--;d=(m%(1<<s));

         int primes[6]={2,3,7,31,61,73},i,a,flag;
         uint64_t x;
         for(i=0;i<6;i++)
         {    if(primes[i]>n)
                      break;
              a=primes[i];
              x=uint64_t(pow(a,d))%n;
              if(x==1 || x==n-1)
                      continue;

              for(int r=1;r<s;r++)
              {       x=(x*x)%n;
                      if(x==1)
                              return 0;
                      if(x==n-1)
                                break;
              }
              if(x!=n-1)
                        return 0;
         }
         return 1;
}
main()
{for(int k=1;k<20;k++) printf("%d is %d\n",k,is_prime(k)); getch();}


On 1/18/12, Sourabh Singh<singhsourab...@gmail.com>  wrote:
@ sunny agrawal

you are right. but i have used check a>n also . no improvement .
i think algo is wrong in later part.. somewhere..

@ Terence

1) pow may not work for big n but , m just checking for n=1..200
    just to check wether algo is right.. and it's not working even for
n=7,19...

2) d,s are also coming fine for small values.. of n

3) for x i have used... 64bit integer.. uint64_t in it's declaration.

i just want to get algo right first then bother about big n ;-)

On 1/18/12, Terence<technic....@gmail.com>  wrote:
1. the computing of d is incorrect.
      d = n-1;
      while((d&1)==0) d>>=1;

2. the accuracy of pow is far from enough. you should implement your own
pow-modulo-n method.

3. for big n, (exceed 32bit), x=(x*x)%n can be overflow also. you may
need to implement your own multiply method in this case.


On 2012-1-18 18:15, Sourabh Singh wrote:
@all output's to above code are just random.. some prime's. found
correctly while some are not

why i used certain primes to check ie.(2,3,31,73,61,7) coz.. its given
n wiki for about 10^15 checking with these is enough..

On 1/18/12, Sourabh Singh<singhsourab...@gmail.com>   wrote:
@ALL hi everyone m trying to make prime checker based on miller-rabin
test . can some1 point out . wat's wrong with the code. thank's alot
in advance...

//prime checker based on miller-rabin test
#include<iostream>
#include<conio.h>
#include<math.h>
int is_prime(int n)
{
          if(n==2 | n==3)
                        return 1;
          if(((n-1)%6!=0&   (n+1)%6!=0) || n<2)
                        return 0;
          int s,d;
          for(s=0;1<<s<n;++s); s--;d=(n%(1<<s));

          int primes[6]={2,3,7,31,61,73},i,a,flag;
          uint64_t x;
          for(i=0;i<6;i++)
          {    flag=0;

               a=primes[i];
               x=uint64_t(pow(a,d))%n;
               if(x==1 | x==n-1)
                          continue;
               for(int r=1;r<s;r++)
               {       x=(x*x)%n;
                       printf("x is %llu\n",x);
                       if(x==1)
                               return 0;
                       else
                               flag=1;
               }
               if(flag)
                       continue;
               return 0;
          }
          return 1;
}
main()
{
    for(int k=1;k<100;k++)
    {
            printf("%d is %d\n",k,is_prime(k));
    }
    getch();
}

--
You received this message because you are subscribed to the Google
Groups
"Algorithm Geeks" group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/algogeeks?hl=en.


--
You received this message because you are subscribed to the Google Groups
"Algorithm Geeks" group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/algogeeks?hl=en.



--
You received this message because you are subscribed to the Google Groups "Algorithm 
Geeks" group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.

Reply via email to