thats a brute force solution...
can u expalin the complexity..i think its O(n^2)
and also there exist no solution for n < 3

On Thu, Jan 19, 2012 at 3:36 PM, bharat b <bagana.bharatku...@gmail.com>wrote:

> @Neeraj : will u pls explain u'r logic ...
>
> On 1/19/12, NEERAJ KODDHAN <neerajdc...@gmail.com> wrote:
> > int[] a = new int[2*n];
> > put(a, n);
> >
> > static void put(int[] a,int i){
> > if(i>0){
> >  for(int j=0;j<a.length-i-1;j++){
> > if(a[j]==0 && a[j+i+1]==0){
> >  a[j]=i;
> > a[j+i+1]=i;
> > put(a, i-1);
> >  a[j]=0;
> > a[j+i+1]=0;
> > }
> >  }
> > }else if(i==0){
> > for (int k : a) {
> >  System.out.print(k +" ");
> > }
> > System.out.println();
> >  }
> > }
> >
> >
> > On Wed, Jan 18, 2012 at 10:04 PM, Coding Geek <codinggee...@gmail.com
> >wrote:
> >
> >> Place N number from 1 to N, in 2N positions in such a way so that there
> >> are
> >>
> >> Exactly ā€œnā€ number of cells between two placed locations of number ā€œnā€.
> >> Write a program to display numbers placed in this way.
> >>
> >> Example:-
> >>
> >> (1) One of the possible placement for 7 numbers in 14 positions is :
> >> 5 7 2 3 6 2 5 3 4 7 1 6 1 4
> >>
> >>
> >>
> >> --
> >>
> >> "To Iterate is Human, To Recurse is Divine"
> >>
> >> --
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>
> **Regards
> *
> * <bagana.bharatku...@gmail.com>
>
> Bharat B | M.Tech II  | Computer Science & Engineering | IITM
> *
> *
> *Ph: +91 8056127652*
>
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>


-- 
Regards
Aditya Kumar
B-tech IV year
Computer Science & Engg.
MNNIT, Allahabad.

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