http://stackoverflow.com/questions/4311694/maximize-the-rectangular-area-under-histogram
it is described here.
On Mon, Jan 23, 2012 at 3:16 PM, Ashish Goel <ashg...@gmail.com> wrote:
> someone said that the solutionhas been given using the stack, can someone
> explain it, i did a lookup in my mail box and the solution for the
> histogram problem is not there. The gif tells how to proceed, however, not
> able to map it to how stack to be used.
>
> Best Regards
> Ashish Goel
> "Think positive and find fuel in failure"
> +919985813081
> +919966006652
>
>
> On Mon, Jan 23, 2012 at 10:57 AM, Ashish Goel <ashg...@gmail.com> wrote:
>
>> You are given an array which represents the heights of every bar of a
>> histogram. Now all these bars are contiguous (juxtaposed wrt each other)
>> and have the same width.
>> For Example, A={2,1,4} represents a histogram having 3 bars of height
>> 2,1and 4 in that order. Now you need to find a rectangle in this histogram
>> that has the maximum area.
>> See figure:
>> http://www.ocf.berkeley.edu/~wwu/YaBBAttachments/hist_rect.gif
>>
>> Time Complexity: O(n)
>> Space Complexity:O(1)
>> let the histogram given is 1,2,1,4,3,2,2,3,1,4,1,1,1,1,1,1
>>
>> the max is 16, when i trying to use Ldistance, it is coming as 10.
>>
>> Alternatively, the logic of finding with all the consecutive bars
>> following a particular bar which are non-ascending is O(n^2)
>>
>>
>> any solutions?
>>
>>
>>
>>
>> Best Regards
>> Ashish Goel
>> "Think positive and find fuel in failure"
>> +919985813081
>> +919966006652
>>
>
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