thanks Dave and Siddhartha sir. i think dave sir misinterpreted the a(n) relation. anyway i wil try to solve this problem using this method. On Thu, Jan 26, 2012 at 1:36 PM, Siddhartha Banerjee < thefourrup...@gmail.com> wrote:
> @dave: > a(n)=a(n-1)+a(n-2)-a(n-5)-2 > is not the same as > b(n) = b(n-1) + b(n-2) - b(n-5) with b(n)=a(n)-2. > b(n) = b(n-1) + b(n-2) - b(n-5) =>a(n)-2=a(n-1)-2+a(n-2)-2-a(n-5)+2 > =>a(n)=a(n-1)+a(n-2)-a(n-5) which is not the same as original relation. > > however the classic approach is still fine, we can have > | a(n+1) | | 1 1 0 0 0 -1 -2| | a(n) | > | a(n) | | 1 0 0 0 0 0 0 | | a(n-1) | > | a(n-1) | | 0 1 0 0 0 0 0 | | a(n-2) | > | a(n-2) | = | 0 0 1 0 0 0 0 | x | a(n-3) | > | a(n-3) | | 0 0 0 1 0 0 0 | | a(n-4) | > | a(n-4) | | 0 0 0 0 1 0 0| | a(n-5) | > | 1 | | 0 0 0 0 0 0 1| | 1 | > > to complete the operation in O(log(n)) > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- With Regards Manish Patel BTech Computer Science And Engineering National Institute of Technology -Allahabad -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
