interesting discussion going on the question, check this link--

http://stackoverflow.com/questions/9442958/find-the-element-occurring-b-times-in-an-an-array-of-size-nkb


--


Amol Sharma
Third Year Student
Computer Science and Engineering
MNNIT Allahabad
 <http://gplus.to/amolsharma99>
<http://twitter.com/amolsharma99><http://in.linkedin.com/pub/amol-sharma/21/79b/507><http://www.simplyamol.blogspot.com/>






On Fri, Feb 17, 2012 at 12:25 PM, atul anand <atul.87fri...@gmail.com>wrote:

> @Siddhartha : doing bitwise addtiton may result into overflow if values
> are large.....
> correct me if i am wrong.
>
> On Fri, Feb 17, 2012 at 10:04 AM, Siddhartha Banerjee <
> thefourrup...@gmail.com> wrote:
>
>> convert the numbers into base k... and do bitwise addition of numbers,
>> where
>> bit(a)+bit(b)=bit(a+b)mod(k)
>> of you convert all the numbers into base k and add them bitwise in a
>> variable say x, then the numbers occuring nk times vanish, and the final
>> result stored in x is a+a+....+a(b times) where a is the number repeating b
>> times...
>> next time go through the array again and see whether any number when
>> added with itself b times gives the same result as x, if yes, out put that
>> number.
>>
>> I had seen a solution to a problem where in an array of size 3n+1, each
>> element except one repeating thrice, we need to find the non repeating
>> element in O(n) time O(1) space, i tried to generalize the proof to fit
>> this case...
>>
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