@umer : dp approach is given in above post.

On Mon, Mar 26, 2012 at 4:11 PM, Umer Farooq <the.um...@gmail.com> wrote:

> Well, they have specified in the question that "you are dealing with
> big-data sets". So, recursion won't be a good option I guess.
>
> Can we solve it with dynamic programming technique?
>
>
> On Mon, Mar 26, 2012 at 2:24 PM, atul anand <atul.87fri...@gmail.com>wrote:
>
>> one way to do it , is say first combination for invoice 80= 50 + 30
>> now remove 80 and 30 from the input bills while finding combination from
>> 210 , check if it is possible
>> if yes , we got one solution
>> not select another invoice combination 80= 50 + 10 + 20
>> now dont consider these values while find combination for 210.
>>
>> i guess there can be better way to solve this......
>>
>>
>> On Mon, Mar 26, 2012 at 2:36 PM, Ankush Bagotra <ankush.bago...@gmail.com
>> > wrote:
>>
>>> Ok now you have combination of each invoice .  What is the approach to
>>> take mutual exclusive combinations for so that sum of all bills equals
>>> sum of all invoices
>>>
>>> On Mon, Mar 26, 2012 at 2:16 PM, atul anand <atul.87fri...@gmail.com>
>>> wrote:
>>> > it is similar to sum-subset problem following recurrance will solve
>>> this
>>> > problem , you need to run algo for each invoice to find all combination
>>> >
>>> > F(n,k) = F(n,k-1) or F(n - a[k], k-1)
>>> > base case :F(0,k)=1 for k>=0
>>> >                         F(n,0)= 0 for n>0.
>>> >
>>> > On Mon, Mar 26, 2012 at 1:34 PM, Ankush Bagotra <
>>> ankush.bago...@gmail.com>
>>> > wrote:
>>> >>
>>> >> There are 210 Invoices and 1700 bills – these bills add up to these
>>> >> invoices
>>> >>
>>> >> The association between  bills and invoices is lost . The only way to
>>> >> match them is by adding them up to correct amounts that are equal to
>>> >> the invoices.
>>> >>
>>> >> For Example :  there were 2 invoices for 80, 210 and you have bills
>>> >> for these 50, 10 ,10, 30 , 20, 70, 100 values
>>> >>
>>> >> One of the possible solution is :
>>> >>
>>> >> 80=50 + 30
>>> >> 210= 10 + 10 +20 + 70 + 100
>>> >>
>>> >> Other possible solution is
>>> >>
>>> >> 80=50 + 10 + 20
>>> >> 210= 30 +20 + 70 + 100
>>> >>
>>> >>
>>> >> What is the best possible way to get all solutions ? Remember you are
>>> >> dealing with big datasets
>>> >>
>>> >> -Kabir
>>> >>
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>
>
>
> --
> Umer
>
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