@Ashgoel: Try this: bool OnesZerosOnes(unsigned int n) { if( !(n & 1) || !(n &= n+1) ) return 0; n |= n-1; return !(n & (n+1)); } Here is how it works: !(n & 1) is true if the number has trailing zeros. If the number has trailing ones, n &= n+1 replaces the trailing ones with zeros. !(n &= n+1) is true if there are only trailing ones, i.e., the original number was zeros followed by ones. n |= n-1 replaces trailing zeros with ones. Thus, if the original number is ones followed by zeros followed by ones, the zeros have been changed to ones. (n & (n+1)) replaces the trailing ones with zeros. If the number is now zero, the number is valid, otherwise the number is invalid. Dave
On Tuesday, April 3, 2012 7:00:36 PM UTC-5, ashgoel wrote: > verify that the bits of a number are in format 1s followed by 0s followed > by 1s like 1110001 is valid but 100100100 is not > > Best Regards > Ashish Goel > "Think positive and find fuel in failure" > +919985813081 > +919966006652 > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/zBATGHVXUTAJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.