+1 adarsh

On Wed, May 2, 2012 at 12:43 PM, adarsh kumar <algog...@gmail.com> wrote:

> Simple, refer this:
> http://www.geeksforgeeks.org/archives/2405
>
>
> On Wed, May 2, 2012 at 1:12 AM, Abhishek Sharma <jkabhishe...@gmail.com>wrote:
>
>> @Bhupendra: your approach is correct but in case the linked lists contain
>> millions of nodes then this might be an overhead.
>>
>> Another approach could be:
>>
>> - Start with the head of of both the lists.
>> - Store (Hash) the addresses to which the current nodes are pointing to,
>> in a hashtable.
>> - while storing (Hashing) also check if the address already exists (for
>> both of them). In case it exists in the hashtable, this address (or node)
>> is the required node else, increment the pointers to the next nodes.
>>
>> This algo will not require traversing the whole lists and will save time.
>>
>> Regards,
>> AB
>>
>>
>> On Tue, May 1, 2012 at 9:36 PM, Umer Farooq <the.um...@gmail.com> wrote:
>>
>>> You don't have to traverse the nodes of two lists simultaneously.
>>>
>>> You have to check if the every node of list one matches with the address
>>> of any node of list two. The first matching address will be the output.
>>>
>>> The worst case running time of this algo will be O(n^2)
>>>
>>>
>>> On Tue, May 1, 2012 at 8:47 PM, rafi <rafiwie...@gmail.com> wrote:
>>>
>>>> i dont understan if i look in the pic i attached then the length of
>>>> the first list is 5 and the length of the second list is 6.
>>>> what should i do now?
>>>> if i traverse the long list 5,6 nodes i dont get to the red node.
>>>> what am i missing?
>>>>
>>>> On 1 מאי, 18:04, Bhupendra Dubey <bhupendra....@gmail.com> wrote:
>>>> > start from head of both and  as soon as one of the list is empty
>>>> means  you
>>>> > hit null
>>>> > start counting the remaining number of nodes in the other list till
>>>> that
>>>> > gets empty.
>>>> >
>>>> > Now the number obtained  above is the difference in length of the two
>>>> list
>>>> > prior to the first common node (the red node). Now again traverse the
>>>> > longer list corresponding to the above count and then start
>>>>  traversing the
>>>> > other list .Stop when two nodes become equal. Home!:)
>>>> >
>>>> > On Tue, May 1, 2012 at 7:55 PM, רפי וינר <rafiwie...@gmail.com>
>>>> wrote:
>>>> > > you have two linked lists that some where combine in to one list.
>>>> > > pic attached to illustrate
>>>> > >  [image: Inline image 1]
>>>> > > you need to find where the two list collide. (in the pic the red
>>>> node)
>>>> >
>>>> > > --
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>>>> > --
>>>> > bhupendra dubey
>>>> >
>>>> >  Untitled.png
>>>> > 14Kהצגהורדה
>>>>
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>>>>
>>>
>>>
>>> --
>>> Umer
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>>
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