i=300 // binary = 00000001 00101100
// in case of little Endien
it will be saved like this :-
00000001
00101100
//suppose int = 2 bytes and char = 1 byte
char *ptr = &i; // take care it *char *ptr* not *int* **ptr*....so what
will happen
*ptr will be pointing to 00101100
*++ptr // now ptr is pointing to 00000001 bcozz it is a char * hence it
will be increment by 1 byte
ptr=2 // now 00000001 will be converted to 00000010
so final value of i becomes 0000001000101100 = 556
now you can try for big endian ....
On Thu, Jun 7, 2012 at 12:27 AM, g4ur4v <gauravyadav1...@gmail.com> wrote:
>
>
> main()
> {
> int i=300;
> char *ptr = &i;
> *++ptr=2;
> printf("%d",i);
> }
>
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