Easy Buddy.. this is primary thing.. Surprise to know that ppls still don't
knw abt this..
for OR:-
if left expr evaluate non zero it won't compute right side.
For And:-
if left expr evalute zero , it won't compute right side
Prem
On Tue, Jun 12, 2012 at 11:10 AM, sengar.mahi <sengar.m...@gmail.com> wrote:
> Nope ,the output is correct.as I had studied somewhere ,i don't remember
> where exactly but
> in (x||y) type condition's,if x evaluates to true( non zero) then value of
> y doesn't matter and is not evaluated and condition turns out to be true
> anyhow without even checking y ,control never goes to y and y is never
> executed;
> now in your case m=++i || ++j && ++k;
> since precedence of && is more than or,so we can take it as m=++i || (++j
> && ++k);
> now expression evaluates to true just by checking i++ which is -2 now(non
> zero) and value of ++j && ++k is not even checked nor changed ,hence both j
> and k remain unchanged.
> This is a correct explanation u can rely an this.
> thank you :)
>
>
> On Tue, Jun 12, 2012 at 2:19 AM, Dave <dave_and_da...@juno.com> wrote:
>
>> This is the result of short-circuit evaluation. See, e.g.,
>> http://en.wikipedia.org/wiki/Short-circuit_evaluation, or this topic in
>> your language reference.
>>
>> Dave
>>
>> On Monday, June 11, 2012 2:28:52 PM UTC-5, ((** VICKY **)) wrote:
>>
>>> #include<stdio.h>int main(){int i,j,k,m,l;
>>> i=-3;
>>> j=2;
>>> k=0;m=++i || ++j && ++k ;printf
>>> <http://www.opengroup.org/onlinepubs/009695399/functions/printf.html>("\n%d
>>> %d %d %d",i,j,k,m);return 0;}
>>>
>>> o/p: -2 2 0 1
>>>
>>>
>>> k should be 1 right????
>>>
>>>
>>> --
>>> Cheers,
>>>
>>> Vicky
>>>
>>> --
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