sry ignore the last comment for i wanted to say -
your algo will work only when the numbers given are consecutive.

--


Amol Sharma
Final Year Student
Computer Science and Engineering
MNNIT Allahabad

<http://gplus.to/amolsharma99>
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On Fri, Jun 15, 2012 at 8:06 PM, Amol Sharma <amolsharm...@gmail.com> wrote:

> @enchantress :
> your algo will work only when the number given are positive.
> --
>
>
> Amol Sharma
> Final Year Student
> Computer Science and Engineering
> MNNIT Allahabad
>  <http://gplus.to/amolsharma99> 
> <http://twitter.com/amolsharma99><http://in.linkedin.com/pub/amol-sharma/21/79b/507><http://www.simplyamol.blogspot.com/>
>
>
>
>
>
>
> On Fri, Jun 15, 2012 at 7:01 PM, shiv narayan 
> <narayan.shiv...@gmail.com>wrote:
>
>> this is the running code to find no of triangles using brute force
>> technique
>> logic: in a triangle having sides a,b,c; then a+b>c(if c is greatest side)
>> correct me if i am wrong.
>>
>>  #include<iostream>
>> #include<conio.h>
>> using namespace std;
>> int max(int a,int b,int c)
>> {
>>     return ((a>b?a:b)>c?(a>b?a:b):c);
>> }
>> int main()
>> {
>> int n,a[120],t,p,q;
>> cin>>t;
>> while(t--)
>> {
>> cin>>n;
>> for(int i=0;i<n;i++)
>> cin>>a[i];
>> int i,j,no_of_triangles=0,sum=0,largest_edge;
>> for(i=0;i<n-2;i++)
>> {
>> for(j=i+2;j<n;j++)
>> {
>> sum=a[i]+a[i+1]+a[j];
>> largest_edge=max(a[i],a[i+1],a[j]);
>> if(sum-largest_edge>largest_edge)
>> {
>> no_of_triangles++;
>> cout<<a[i]<<" "<<a[i+1]<<" "<<a[j]<<"\n";}
>>
>> }
>> }
>> cout<<no_of_triangles<<endl;
>> }
>> getch();
>> return 0;
>> }
>>
>>
>> On Wednesday, 13 June 2012 22:18:01 UTC+5:30, payel roy wrote:
>>
>>>
>>> Let's say there are N sides are given. Length of them are like
>>> 1,2,3,4,5,....N.
>>>
>>> How do you determine how many tri-angles can be made out of these N
>>> sides?
>>>
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>

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