@umer
it's not random,but biased

On Wed, Jun 20, 2012 at 11:16 AM, Umer Farooq <the.um...@gmail.com> wrote:

> Hmmm, true. That's what I expected in this solution. Similarly, we can get
> 3 by (3,3) (1,2)
>
> However, did you take a look at the other solution I proposed? I guess
> that solves the problem to some extent.
>
>
> On Tue, Jun 19, 2012 at 7:18 PM, Sourabh Singh 
> <singhsourab...@gmail.com>wrote:
>
>> @Umer and Navin :
>> 1 is generated by (1,3) only.
>> 2 is generated by (1,1) and (2,3).
>>
>> so given solution is wrong
>>
>>
>> On Tue, Jun 19, 2012 at 5:17 AM, Sourabh Singh 
>> <singhsourab...@gmail.com>wrote:
>>
>>> @ *ALL*
>>>
>>>     please. post along with your method .
>>>     proof than it make's equal distribution over the given range.
>>>
>>> On Tue, Jun 19, 2012 at 4:47 AM, Navin Kumar 
>>> <algorithm.i...@gmail.com>wrote:
>>>
>>>> @Umer:
>>>>
>>>> rand(5) + (rand(5)%2): => it will never give 6 because for rand(7)
>>>> range will be 0-6.
>>>> So better try this: rand(5) + (rand(5)%3).
>>>>
>>>>
>>>> On Tue, Jun 19, 2012 at 2:45 PM, Umer Farooq <the.um...@gmail.com>wrote:
>>>>
>>>>> rand(5) + (rand(5)%2);
>>>>>
>>>>>
>>>>> On Tue, Jun 19, 2012 at 12:30 PM, Sourabh Singh <
>>>>> singhsourab...@gmail.com> wrote:
>>>>>
>>>>>> @ sry
>>>>>> condition should be:
>>>>>>
>>>>>> if(20*prob <= 500/7) :-)
>>>>>>
>>>>>>
>>>>>> On Tue, Jun 19, 2012 at 12:26 AM, Sourabh Singh <
>>>>>> singhsourab...@gmail.com> wrote:
>>>>>>
>>>>>>> @ALL
>>>>>>>
>>>>>>> Given a random number generator say r(5) generates number between
>>>>>>> 1-5 uniformly at random , use it to in r(7) which should generate a 
>>>>>>> random
>>>>>>> number between 1-7 uniformly at random
>>>>>>>
>>>>>>> i have seen this on many site's but not a single correct solution.
>>>>>>> all solution's posted got rejected by someone else.:
>>>>>>> plz.. suggest some algo :
>>>>>>>
>>>>>>> my aprroach:
>>>>>>>
>>>>>>> let's assume a rectangle :
>>>>>>>
>>>>>>> 100      |___________________
>>>>>>>             |___________________|______
>>>>>>> 500/7   |                                      |            |
>>>>>>>             |                                      |            |
>>>>>>>             |___________________|______|
>>>>>>>             0     1      2      3     4      5     6    7
>>>>>>> now :
>>>>>>>
>>>>>>> let : num  = rand(5);
>>>>>>>        prob = rand(5);
>>>>>>>
>>>>>>>        if(prob <= rand(5))
>>>>>>>                         print  num
>>>>>>>        else
>>>>>>>                         print  5 + num*(2/5)
>>>>>>>
>>>>>>>
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>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> Umer
>>>>>
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>>>>>
>>>>
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>>>
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>
>
>
> --
> Umer
>
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>



-- 
Abhishek Sharma
Under-Graduate Student,
PEC University of Technology

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