@deepika-ur program was running only for 1 iteration because of ur
condition in the inner loop(i.e. j<MAX-i should be either j<MAX-1 or
j<MAX-i-1)

#define MAX 10
void sort(int a[],int *ptr[])
{
     //where p[i]=&a[i] ;
       int i,j,*x ;
       for(i=0;i<MAX;i++)
       {
       printf("iterations %d",i);
                for(j=0;j<MAX-1;j++)
                {
                if((*(ptr[j]))> (*(ptr[j+1]))) //this means A[j] > A[j+1]
                {
                        x = ptr[j+1];
                        ptr[j+1] = ptr[j];
                        ptr[j] = x;
                }
        }
        }//end of outer loop
         for(i=0;i<MAX;i++){
                          printf("%d",*ptr[i]);
                          }
}//end of function
main(){
       int *p[MAX],i,ar[MAX];
       printf("enter the array");
       for(i=0;i<MAX;i++){
                          scanf("%d",&ar[i]);
                          p[i]=&ar[i];
                          }
       sort(ar,p);
       getch();
       }


On Fri, Jun 22, 2012 at 2:13 PM, deepikaanand <swinyanand...@gmail.com>wrote:

> //To sort an array of integers by not moving the element itself ..we
> can only use array of pointers...to adjust the pointers
> I have used bubble sort....but it only runs for the first pass when i
> = 0 ..but not for further values of i
>
> void sort(int A[])
> {
> int i ;
>  //int **a = &ptr[0];
>        for(i=0;i<MAX-1;i++)
>        {
> cout<<"\n case number = "<<i;
>        for(int j = 0;j<MAX-i;j++)
>        {
>                if((*(ptr[j]))> (*(ptr[j+1]))) //this means A[j] > A[j+1]
>                {
>                        int *a = ptr[j+1];
>                        ptr[j+1] = ptr[j];
>                        ptr[j] = a;
>                        display();
>
>                }
>        }
>        }//end of outer loop
> }//end of function
>
>
> full code :----
> http://ideone.com/IeSRQ
>
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-- 
Vindhya Chhabra

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