@Prakash The Pattern given by u is because factorial (n) is always *even *so u can always divide them in two equal part . what about 1/6= 1/8 + 1/24 ( 6 = factorial (3))
On Mon, Jun 25, 2012 at 11:24 PM, Kishore <kkishoreya...@gmail.com> wrote: > This is from interviewstreet named with equations > > > On Mon, Jun 25, 2012 at 11:19 AM, prakash y <yprakash....@gmail.com>wrote: > >> 2! - x=y=4 >> 3! - x=y=12 >> 4! - x=y=48 >> 5! - x=y=240 >> 6! - x=y=1440 >> I don't have proof to prove x = y always. >> But if x=y, then the answer should be x=y=2*n! >> >> On Mon, Jun 25, 2012 at 5:04 PM, Roshan <kumar...@gmail.com> wrote: >> >>> Few Months back I found the problem >>> on Code Sprint >>> 1/x + 1/y = 1/N! (N factorial). For large value of N >>> we have to find the par of (X,Y) which satisfy the equation >>> my sol was slow , >>> can any pleas help me . >>> >>> Thanks >>> Kumar Vishal >>> >>> -- >>> You received this message because you are subscribed to the Google >>> Groups "Algorithm Geeks" group. >>> To view this discussion on the web visit >>> https://groups.google.com/d/msg/algogeeks/-/PeqVSr7OlFsJ. >>> To post to this group, send email to algogeeks@googlegroups.com. >>> To unsubscribe from this group, send email to >>> algogeeks+unsubscr...@googlegroups.com. >>> For more options, visit this group at >>> http://groups.google.com/group/algogeeks?hl=en. >>> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- Regards Kumar Vishal _________________________________________ *http://wethecommonpeople.wordpress.com/ * *h**ttp://kumartechnicalarticles.wordpress.com/<http://kumartechnicalarticles.wordpress.com/> * _________________________________________ -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
