make size of both array by adding '0' in front of smaller array
then
int carry=0;
for(i=array.size();i>=0;i--)
{
sum[i]=carry+arrayA[i]+arrayB[i];
carry=sum[i]/10;
sum[i]=sum[i]%10;
}
then reverse and print sum
On Tue, Jun 26, 2012 at 3:40 PM, Ashish Goel <ashg...@gmail.com> wrote:> > Best Regards > Ashish Goel > "Think positive and find fuel in failure" > +919985813081 > +919966006652 > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- Thanks & Regards Amritpal singh -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
