arr1 = (int *)malloc(sizeof(int) * ncols); // memory allocated for 1st
row
arr2 = (int **)malloc(sizeof(arr1) * nrows);
I haven't tried it.So,please correct me if i am wrong
On Mon, Jul 2, 2012 at 12:55 PM, Rishabh Agarwal <rishabh...@gmail.com>wrote:
>
> nrows: number of rows
> ncols: number of columns
>
> int **arra = (int **)malloc( sizeof(int*) * nrows );
> int *ar = (int *)malloc( sizeof(int) * nrows * ncols );
> for( int a = 0; a < nrows; a ++ ) {
> arra[a] = ar + ncols * a;
> }
>
> now index of array i and j can be accessed as arra[i][j]
>
>
>
> On Friday, June 29, 2012 4:46:18 PM UTC+5:30, rahul r. srivastava wrote:
>>
>> implement a 2d matrix using only 2 mallocs.
>>
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