the code works fine only in case of duplicates , but if we consider
string to be non duplicates like say :"abc" then all permutation cant be
obtainned .
On Wed, Jul 4, 2012 at 12:31 PM, atul anand <atul.87fri...@gmail.com> wrote:
> you can use flag[256];
>
> now you just need to check
> loop:
> if (flag[str[i]]==0)
> {
> //swap()
> //permute function call
> //swap()
> flag[str[i]=1;
> }
> done
>
>
> On 7/4/12, atul anand <atul.87fri...@gmail.com> wrote:
> > you can use flag[256];
> >
> > now you just need to check
> > loop:
> > flag[str[i]]==0)
> > {
> > //swap()
> > //permute function call
> > //swap()
> > flag[str[i]=1;
> > }
> > done
> >
> > On 7/3/12, Nishant Pandey <nishant.bits.me...@gmail.com> wrote:
> >> 1) Find all permutations of a string.
> >> 2) Improve it so that the permutations are not repeated, Eg=> string is
> >> "aaaa"
> >> Answer should be just aaaa once not 4! times.
> >>
> >> i want suggestion to improve the recursive code in case of 2) case .
> >>
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