I was trying to solve this.. was somewhat close before I looked at ur 
solution.
But.. equal probability for 1-12 (1 inclusive is a good hint for putting on 
0's)

On Saturday, 7 July 2012 15:58:35 UTC-4, Abhishek Sharma wrote:
>
> @Raj: trace karke dekh na yaar.... when u have 3 0s and 3 6s.. the sum 
> distribution would look like this: 
>
> given below are the possibilities: 
>
> Combination of 1,2,3,4,5,6 with 0
> 1+0 = 1
> 2+0 = 2
> 3+0 = 3   
>
> OR
>
> 4+0 = 4
> 5+0 = 5
> 6+0 = 6
>
> Combination of 1,2,3,4,5,6 with 6
>
> 1+6 = 7
> 2+6 = 8
> 3+6 = 9
>
> OR 
>
> 4+6 = 10
> 5+6 = 11
> 6+6 = 12
>
> ho gye na evenly distribute :)
>
> On Sat, Jul 7, 2012 at 10:24 PM, Prakhar Jain <jprakha...@gmail.com>wrote:
>
>> Label 3 of the faces with 0 and other 3 faces with 6.
>>
>>
>> -- 
>> Prakhar Jain
>> IIIT Allahabad
>> B.Tech IT 3rd Year
>> Mob no: +91 9454992196
>> E-mail: rit2009...@iiita.ac.in
>>           jprakha...@gmail.com
>>
>>
>>
>> On Sat, Jul 7, 2012 at 12:52 AM, Hraday Sharma <hradaysha...@gmail.com>wrote:
>>
>>> You are given 2 dice. Both are fair. One of the dice has no numbers 
>>> printed on it. You have to label the unmarked dice such that when both the 
>>> dice are thrown, the sum on the faces is evenly distributed between 1 and 12
>>>  .
>>>
>>>
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