@abinesh:
The solution given has a very very high complexity. as it finds all
possiblilities  and tests each one of it.
is it *n*[(2n!)/(n! * n!)]* --> This is exponential solution. I am not sure
but, there must be a DP solution to this .

--Sravan Reddy



On Wed, Jul 11, 2012 at 12:15 AM, arumuga abinesh
<arumugaabin...@gmail.com>wrote:

> http://www.geeksforgeeks.org/archives/17743
>
> Using the above problem we get all possible merges , at each possible
> merge, we can calculate the sum.
>
> On 7/11/12, Mr.B <sravanreddy...@gmail.com> wrote:
> > I think you missed the question:
> > Its a stable merge. (order of elements in each array should be same)
> > Sorting will destroy the original order.
> >
> > Thanks,
> > Mr.B
> > [Please include complexities and pseudo-code]
> >
> > On Tuesday, 10 July 2012 16:18:04 UTC-4, Akshat wrote:
> >>
> >> Here you have to first sort both the arrays A and B and merge both the
> >> arrays to form the sorted array C
> >>
> >> --
> >>
> >>
> >> Akshat Sapra
> >> Under Graduation(B.Tech)
> >> IIIT-Allahabad(Amethi Campus)
> >> *--------------------------------------*
> >> sapraaks...@gmail.com
> >> akshatsapr...@gmail.com
> >> rit20009008@ <rit20009...@gmail.com>iiita.ac.in
> >>
> >
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