lets call the additional pointer as child. find the tail and keep attaching
to tail if there is a child...
struct node * makeDLL(struct node *pDLL) {
if (!pDLL) return pDLL;
struct node *pTail = pDLL;
while (pTail->next) pTail = pTail->next;
struct node *pCurr = pDLL;
while (pCurr) {
if (pCurr->child) {
pTail->next = pCurr->child;
pCurr->child->prev = pTail;
while (pTail->next) pTail = pTail->next;
}
pCurr= pCurr->next;
}
return pDLL;
}
Best Regards
Ashish Goel
"Think positive and find fuel in failure"
+919985813081
+919966006652
On Thu, Aug 2, 2012 at 5:45 PM, Navin Kumar <algorithm.i...@gmail.com>wrote:
> @sahil: Please elaborate your question. I didn't understand your question.
>
> what is straight doubly linked list?? How many pointers each node have??
>
>
>
> On Thu, Aug 2, 2012 at 4:26 PM, Amit Basak <abas...@gmail.com> wrote:
>
>> Does each node in the list have three pointers?
>> What do you mean by straight doubly link list?
>>
>>
>> Thanks,
>> Amit
>>
>>
>>
>>
>>
>> On Wed, Aug 1, 2012 at 7:25 PM, sahil gupta <sahilgupta...@gmail.com>wrote:
>>
>>> There is doubly link list and each node is having another pointer which
>>> is points to another doubly link list or points to null.
>>> You need make it straight doubly link list.
>>> Provide the efficient code.
>>>
>>> Sahil Gupta
>>>
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